Jul 29, 2009 · The third way of initializing is useful when you declare an array first and then initialize it, pass an array as a function argument, or return an array. The explicit type is required.

That is why you get a NullPointerException You need to create objects separately and assign the reference. There are 3 steps to create arrays in Java - Declaration – In this step, we specify the data …

Dec 21, 2009 · When assigning a new array to a declared variable, new must be used. Even if you correct the syntax, accessing data[10] is still incorrect (You can only access data[0] to data[9] …

@Terence: It does the same as the first: It creates an array of string array references, initialized to the values array1, array2, array3, array4 and array5 - each of which is in itself a string array reference.

In Java 8, we can do a kind of generic array creation using a lambda or method reference. This is similar to the reflective approach (which passes a Class), but here we aren't using reflection.

Read user input into a variable and use its value to initialize the array. myArray = new int[someVarSetEarlier] if you want to get the size in advance or use a List if you want the length of …

In java 6 org.json.JSONArray contains the put method and in java 7 javax.json contains the add method. An example of this using the builder pattern in java 7 looks something like this:

For type boolean, the default value is false. For all reference types, the default value is null. By Considering all this you don't need to initialize with zero values for the array elements because by …

I am wanting to create an array of arraylist like below: ArrayList<Individual> [] group = new ArrayList<Individual> () [4]; But it's not compiling. How can I do this?

Is there any way in java to return a new array without assigning it first to a variable? Here is an example: public class Data { private int a; private int b; private int c; privat...